Question

The present population of a village is 5408.if it has increased at the rate of 4%every year.what was its population 2 years ago

Answer 1

$p {(1 + \frac{r}{100} )}^{2} = 5408 \\ p = 5408 \times {( \frac{100}{104} })^{2} = 5000$
here p is population ago 2 years

Answer 2

Answer:

To determine the population of the village two years ago, we can use the formula for population growth:

Step-by-step explanation:

P(t) = P0 * (1 + r)^t

Where:

P(t) is the population at time t (in years)

P0 is the initial population

r is the annual growth rate (expressed as a decimal)

t is the number of years

We know that the present population of the village is 5408 and that it has been growing at a rate of 4% per year. Therefore:

P0 = 5408

r = 0.04

t = 2

We can substitute these values into the formula to find the population 2 years ago:

P(2) = 5408 * (1 + 0.04)^2

P(2) = 5408 * 1.04^2

By calculating this, we found the population 2 years ago is P(2) = 5408 * 1.04^2 = 4907.0696.

So, the population of the village 2 years ago was around 4907.

To know more about the population, from the given link.

https://brainly.in/question/17630618

To know more about population growth, from the given link.

https://brainly.in/question/15517843

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