the present population of s town is 798600. if it increased at the rate of 10% every year , what was it's population 3 years ago
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Here is your answer :-
Present population of town = 22000
Rate of increase in population annually = 10%
Let the population 1 year ago be x .
Now,
(x + 10% of x) = 22000
(x + x/10) = 22000
11x/10 = 22000
x = 22000 × 10/11
x = 20000
So,
The population 1 year ago will be 20000.
Hope my answer will be helpful to you
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