Math, asked by RAAGA666, 10 months ago

the present population of s town is 798600. if it increased at the rate of 10% every year , what was it's population 3 years ago

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Answers

Answered by Anonymous
5

Answer:

it is a example u can read this to solve ur questions

Here is your answer :-

Present population of town = 22000

Rate of increase in population annually = 10%

Let the population 1 year ago be x .

Now,

(x + 10% of x) = 22000

(x + x/10) = 22000

11x/10 = 22000

x = 22000 × 10/11

x = 20000

So,

The population 1 year ago will be 20000.

Hope my answer will be helpful to you

Read more on Brainly.in - https://brainly.in/question/1560413#readmore

Answered by ritvik86
0

Step-by-step explanation:

its yur solution dear....

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