Math, asked by anamikasahu350, 9 months ago

The present population of the town is 1,28,000. If the rate of increase of the population
is 5 percent annually then what would be the population of the town after 3 years?​

Answers

Answered by sheikmelody
5

Step-by-step explanation:

  • Given: present population=1,28,000; Rate of increase of population annually=5%
  • Then,let x be the population after 3 years
  • Present population= 128000=5% of 128000=5/100×128000=6400
  • Increase in population after 1 year= 128000+6400=134400
  • After 2 years= 5/100*134400+134400=140120
  • After 3 years= 5/100*140120+140120= 147126
  • This is the answer=1, 47,126

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Answered by av60464
1

Step-by-step explanation:

Given population of the town=128000

So 128000×5/100+128000=134400

Given population for first year=134400

Now for second year=134400×5/100+134400=141120

For 2nd year=141120

Similarly for third year =141120×5/100+141120 =148176

So given population for third year=148176

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