Question

The present population of the village is 5000. The number of males have increased by 5 percent and number of females by 3 percent after one year. The population after one year is 5212. Find the no of males and females at present?

Answer 1

$et \: males \: be \: x \\ and \: femaes \: be \:( 5000 - x)$

$\frac{105}{100} \times x + \frac{103}{100} \times (5000 - x) = 5212$

$105x + 515000 - 103x = 521200$

$2x = 521200 - 515000$

$2x = 6200$

$x = 3100$

no.of nales=3100 &

fenales=1900

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