Question

The present
present age g
is & 28
bhuvan is
oge
ather's a
father
Syres
you
mo
and his
28 yrs
In how
years
will the
be
twice the
n
Son
and
hing
Age of
१​

Answer 1

Answer:

Let F = Father and S = Son

What we know:

Father is 28 years older than his son. If we put this statement in mathematical terms we get F = S+28 (equation i)

The sum or total of their ages when combined is 58 years. In mathematical terms that tells us that F + S = 58 (equation ii)

Solve using the equations we pulled from what we know.

We know that F = S+28 so we can plug this equation into variable F in equation ii to get:

F + S = 58 (substitute F with F = S+28)

S + 28 + S = 58 (combine like terms)

28 + 2S = 58 (solve for variable S)

2S = 58 — 28 (combine terms)

2S = 30 (divide each side by 2 to isolate variable S)

S = 15 or the son is 15 years old

Now that we know the sons age (S = 15), we can solve for F or the father's age using the same method of substitution:

We know from the initial facts provided that F = S + 28 AND that F + S = 58 . We can now substitute S with 15 in either equation to solve for F.

Option 1 using equation i: F = 15 + 28. Therefore F = 43

Option 2 using equation ii: F + 15 = 58. Solve for F. F = 58 — 15 or F = 43

Solution

After solving via substitution, we find that:

Father = 43

Son = 15