The present price of a scooter is rs 7290. If it's value decreases every year's by 10%,then find its value before 3 years
Answers
Answered by
86
Let the cost of the scooter before 3 years was x.
Given that amount = 7290 rupees, r = 10%, n = 3 years.
We know that A = P(1 - r/100)^n
7290 = x(1 - 10/100)^3
7290 = x(9/10)^3
7290 = x * (729/1000)
7290 = 729x/1000
7290 * 1000 = 729x
7290000 = 729x
7290000/729 = x
10000 = x.
Therefore the value of the scooter before 3 years ago = 10000 rupees.
Hope this helps!
Given that amount = 7290 rupees, r = 10%, n = 3 years.
We know that A = P(1 - r/100)^n
7290 = x(1 - 10/100)^3
7290 = x(9/10)^3
7290 = x * (729/1000)
7290 = 729x/1000
7290 * 1000 = 729x
7290000 = 729x
7290000/729 = x
10000 = x.
Therefore the value of the scooter before 3 years ago = 10000 rupees.
Hope this helps!
Answered by
14
Answer:
Principal Amount = 10,000
Step-by-step explanation:
i = R/100
i = 10/100
i = 0.1
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