Question

The present ratio of ages of A&B was 1:3 and after six years are ratio becomes 2:3.find the sum of present age of A&B. IP​

Answer 1

Answer:Let suppose in present, Age of A is x and Age of B is y.

Now ratio of ages of A and B before ten years is 3:5.

So (A/B)-> Before ten years=3/5

so (x-10)/(y-10) =3/5 ………………………………………….(1)

Now the ratio of their present ages is 2:3.

So, (x/y)=2/3 …………………..(2)

From Equation (1) we get,

5x-3y=20

and from Equation (2) we get,

3x-2y=0

From these two equation we can get values of x and y.

x=40

y=60

Now Difference between their ages is = 60–40 = 20

So,final answer is 20.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

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