The pressure acting in a liquid of density 600 kg/m3 at a depth of 15 m from the surface of the liquid
is____. (g = 10 m/s2
)
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Answer:
Explanation:
p = p₀ + ρgh
= 1.01 × 10⁵ + 600 × 10 × 15
= 1.01 × 10⁵ + 0.9 × 10⁵
= 1.91 × 10⁵ Pascal
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