Question

The pressure at a depth of 4.4m below the free surface of oil of specific gravity 0.9 is?​

Answer 1

Answer:

Pressure in a fluid with a constant density

∫pp0dp=−∫−h0ρgdyp−p0=ρghp=p0+ρgh. Hence, pressure at a depth of fluid on the surface of Earth is equal to the atmospheric pressure plus ρgh if the density of the fluid is constant over the height, as we found previously.

Explanation:

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