Physics, asked by Rangar5409, 8 months ago

The pressure at a point in water is 10 N//m^(2). The depth below this point where the pressure becomes double is (Given density of water = 10^(3) kg m^(-3), g = 10 m s^(-2))

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Answered by Anonymous
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pressure at a point in water is 10 N//m^(2). The depth below this point where the pressure becomes double is (Given density of water = 10^(3) kg m^(-3), g = 10 m s^(-2))

Water pressure at a point in water is 10 N//m^(2). The depth below this point where the pressure becomes double is (Given density of water = 10^(3) kg m^(-3), g = 10 m s^(-2)) falling down at the rate of 1.8 kgper minute from a vetical tube. The radius at the bottom of the tube is 0.004 m and pressure around it is 0.76m of Hg. The diameter of the tube at a height of 0.5 mfrom the bottom is 0.005 m. find the pressure at that point.

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