the pressure at the base of a column of liquid of length L and held at an angle theta to the vertical is
(a) p(rho)gl
(b) pgl sin theta
(c) pg cos theta
(d) pgl cos theta
plz do anwer fast.....
Answers
Answer:
Pressure at the base of a liquid column =hdg
Here h=height of the column
d=density of liquid
g=acceleration due to gravity
since the column is inclined at an angle θ the vertical height=l cosθ
Pressure=lcosθ*d*g
=ldgcosθ
Here P=d=density
so option (d) is correct
=pgl cosθ
Given : A column of liquid of length L is held at an angle θ with the vertical as shown in figure.
To find : pressure exerted by liquid at the base of column , P = weight along plane of column/cross sectional area
= mgcosθ/A
we know, mass = density × volume
m = ρ × AL
so, P = (ρ AL)cosθ/A = ρgLcosθ
Therefore pressure exerted by liquid at the base is ρgLcosθ.
So, option (d) is correct choice.
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