Physics, asked by amenafirdous44516, 3 days ago

The pressure difference across the surface of a spherical water drop of radius 1mm and surface tension 0.07N/m is A) 28pa B) 35pa C) 140 pa D)280pa​

Answers

Answered by viswadevi777
5

I thing answer is (c) 140 pa

Answered by kamalbhagchandani999
0

Answer:

option:- c)

Explanation:

Radius (r) = 1mm = 0.001m.

Surface Tension (T) = 0.07 N/m

To find:- Pressure difference (Pi - Po)

Solution:-

We know: Pi-Po = 2T/r

∴ Pi-Po = 2 x 0.07/ 0.001 = 14/0.1

∴ Pi-Po = 140 Pa.

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