The pressure difference across the surface of a spherical water drop of radius 1mm and surface tension 0.07N/m is A) 28pa B) 35pa C) 140 pa D)280pa
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I thing answer is (c) 140 pa
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0
Answer:
option:- c)
Explanation:
Radius (r) = 1mm = 0.001m.
Surface Tension (T) = 0.07 N/m
To find:- Pressure difference (Pi - Po)
Solution:-
We know: Pi-Po = 2T/r
∴ Pi-Po = 2 x 0.07/ 0.001 = 14/0.1
∴ Pi-Po = 140 Pa.
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