Question

The pressure exerted by 12 g of an ideal gas at temperature t°C in a vessel of volume V litre is one atm. When the temperature is increased by 10 degrees at the same volume, the pressure increases by 10%. Calculate the temperature t and volume V. (Molecular weight of the gas = 120.)

Answer 1

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Answer 2

Answer:Case I : GivenP = 1 atmw = 12 gT = (t+273)KV = V litreCase ii :T = (t+283)KP = 1 + 1010010100 = 1.1 atmw = 12 gV = V lUsing gas equationCase I : 1×V=12m×R(t+273)1×V=12m×R(t+273) ----(i)Case II : 1.1×V=12m×R(t+283)1.1×V=12m×R(t+283) ----(ii)By equation (i) and (ii)1.11=t+283t+2731.11=t+283t+273∴1.1t+300.3=t+283∴1.1t+300.3=t+2830.1t = -17.3t=−173∘Ct=−173∘C = 100KAlso from case I (Since m = 120)1×V=12120×0.082×1001×V=12120×0.082×100V = 0.82 l

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