The pressure exerted by 12 gm of an ideal gas at T°c in a V (l) vessel is 1 atm when the temprature is increased by 10°c at the same volume pressure increased by 10% if the molar of the gas is 120, find T and V
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(I) Given P = 1 atm, w = 12 g; T = (t + 273)K; V = V litre
(II) If T = t + 10 + 273 = t + 283 K; V = V litre,
P = 1 + 10/100 = 1.1 atm
Using gas equation, PV = w/m RT
Case I. 1 * V = 12/m R (t + 273) ….(1)
Case II. 1.1 * V = 12/m R (t + 283) ….(2)
From (1) and (2), t = - 137oC or t = 100 K
Also from (1), on substituting t and m (120), V = 0.82 litre
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