Question

the pressure exerted by a block of wood is 40pa.If the force exerted by the block is 80N,what is the surface area of the wood?( plz gyes can u all help me to answer my question ) Science questions​

Answer 1

Given :-

• The pressure (P) exerted by a block of wood = 40pa.
• The force(F) exerted by the block = 80N.

To Find :-

• The surface area (A) of the wood.

Solution :-

As we know that,

${ \boxed{ \tt{ \red{P = \frac{F}{A}}}}}$

[ Putting values ]

$\large \mapsto\tt \: 40 = \frac{80}{A}$

$\large \mapsto \tt \: 40 \times A = 80$

$\large \mapsto \tt \: A = \frac{ \: \cancel{80N}}{ \cancel{40N}/m {}^{2} }$

$\mapsto\boxed{\large\tt \blue{\: Area \: = 2m {}^{2} }}$

Hence,

• The surface area of the wood is 2m².

Answer 2

Explanation:

ᴛʜᴇ sᴜʀғᴀᴄᴇ ᴀʀᴇᴀ ᴏғ ᴛʜᴇ ᴡᴏᴏᴅ ɪs 2m²..........