The pressure exerted by a cube of side 0.03 m on a surface is 10 Pa. Calculate
the thrust exerted by the cube.
shreyash62:
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pressure =force/area
10pa=x/0.03
x=0.03*10
x=0.3N (newton)
=====
NOTE ..MORE THE AREA OF CONTACT ...MORE PRESSURE WILL B REQUIRED
HOPE THIS HELPS U ..SORRY FR MISTAKES
MARK ME BRAINLIEST IF THIS SATISFY U
THANKS
10pa=x/0.03
x=0.03*10
x=0.3N (newton)
=====
NOTE ..MORE THE AREA OF CONTACT ...MORE PRESSURE WILL B REQUIRED
HOPE THIS HELPS U ..SORRY FR MISTAKES
MARK ME BRAINLIEST IF THIS SATISFY U
THANKS
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