Question

The pressure exerted by a cubical block of side 3cm
on the surface is 5pa. calculate the force of the block.
​

Answer 1

Answer:

Area = 3cm×3cm=9cm ^2 = 9*10^-4m^2

 

& Pressure exterted = 5Pa

Since Pressure =   force/area

 Force = Pressure × Area

               Force = 9×10^-4*5N

        = 45×10 ^-4N

Answer 2

Answer:

Force of the block =

Explanation:

pressure =5pa

surface area of the side of cubical block= 3×3=9cm square=9/10000m square

as pressure =force

surface area

so,

5 = force ÷ 9

10000

5= force × 10000

9

force = 5×9

10000

force = 0.0045 N