The pressure exerted by a force acting normally on a surface having area 0.1 m^2 is 1000Nm^-2. Find the force applied.
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Answered by
2
area =0.1m^2
pressure=1000Nm^2
pressure=force/area
1000=force/0.1
force=1000*0.1
force=100N
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pressure=1000Nm^2
pressure=force/area
1000=force/0.1
force=1000*0.1
force=100N
hope it helps u mate...
pls mark me brainliest
nomingangbo:
Sorry I am new here so I don’t know how to mark brainliest
Answered by
1
Pressure = force/ area
1000= force / 0.1
1000×0.1 =force
100 N = force
Mark as brainliset please
1000= force / 0.1
1000×0.1 =force
100 N = force
Mark as brainliset please
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