the pressure exerted by a force of 50 Newton normal to the nail of area 1 mmsquare is
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P=F/A
=50/1*10^-6
=5*10^7 pascal
=50/1*10^-6
=5*10^7 pascal
Anonymous:
bro check ur answer once
np
Answered by
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HEY BUDDY...!!!
HERE IS UR ANSWER...
______________________
▶️ We know Pressure is ratio of force to area on which force is applied , i.e
⏺️ P = F / A_____( 1 )
▶️ Where ,
⏺️ Pressure ( P ) = ?
⏺️ Area ( A ) = ( 1 m m )^2 = ( 10^-3 m )^2 = 10^-6 m^2
⏺️ Force ( F ) = 50 N
▶️ By Eqn ( 1 )
=> P = 50 / 10^-6
=> P = 50 × 10^6
=> [ P = 5 × 10^7 N / m^2 or Pa ( Pascal ) ] ✔️✔️
HOPE HELPED..
JAI HIND!!
:-)
HERE IS UR ANSWER...
______________________
▶️ We know Pressure is ratio of force to area on which force is applied , i.e
⏺️ P = F / A_____( 1 )
▶️ Where ,
⏺️ Pressure ( P ) = ?
⏺️ Area ( A ) = ( 1 m m )^2 = ( 10^-3 m )^2 = 10^-6 m^2
⏺️ Force ( F ) = 50 N
▶️ By Eqn ( 1 )
=> P = 50 / 10^-6
=> P = 50 × 10^6
=> [ P = 5 × 10^7 N / m^2 or Pa ( Pascal ) ] ✔️✔️
HOPE HELPED..
JAI HIND!!
:-)
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