Physics, asked by suramauma, 9 months ago

The pressure exerted by a four legged table of weight 100newton is 40000pa
Calculate the area of each leg of the table at the point of contact with floor

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Answered by abdul9838

$<b> <body \: bgcolor = "skyblue">$

$\bf \red{hey \: mate \: here \: is \: answer} \\ \\ \bf \red{ \huge \: solution} \\ \\ \bf \pink{as \: given} \\ \\ \bf \pink{pressure(p) = 40000 \: pa} \\ \\ \bf \pink{f = 100 \: n} \\ \\ \bf \pink{as \: we \: know \: that} \\ \\ \bf \pink{pressure(p) = \frac{force(f)}{area(a)} } \\ \\ \bf \pink{40000= \frac{100}{a} } \\ \\ \bf \pink{a = \frac{ \cancel{100}}{400 \cancel{00}} } \\ \\ \bf \pink{a = \frac{1}{4 \times 100} } \\ \\ \bf \red{a = 0.25 \times \frac{1}{100} } \\ \\ \bf \pink{a = 0.0025}$

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The pressure exerted by a four legged table of weight 100newton is 40000pa Calculate the area of each leg of the table at the point of contact with floor

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The pressure exerted by a four legged table of weight 100newton is 40000pa
Calculate the area of each leg of the table at the point of contact with floor