The pressure exerted by the cubical block of side 3cm on the surface is 5Pa.Calculate the force of the block.
Answers
Answered by
1
Explanation:
side = 3cm
area = 3×3=9cm sq.
pressure = 5 Pa
force = pressure ×area
= 5×9
= 45 N
therefore, the force is of 45 N.
Answered by
0
Answer:
F=A×P
Area= side 3cm, S×S = 3×3 = 9cm²
Pressure = 5pa
Force = A×P = 9cm×5pa = 45N
:
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