The pressure exerted by the weight of a cubical
block of side 50 cm on the surface is 25 Pa. The
weight of the block is
(1) 31.25 N
(2) 625 N
(3) 62.5 N
(4) 6.25 N
Answers
Answered by
0
Answer:
6.25 N
Explanation:
P = F/A = W/A
so, W = PA = 25 * 0.5^2 = 6.26 N
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