the pressure exerted by the weight of the cuboidal block of side 3 CM on the surface is 5 PA. calculate the weight of block
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Cubical block of side = 3cm = 0.03m
Area of base = 0.03m×0.03m
= 0.0009 m^2
So, we can write as 9×10^-4
Pressure = Force /Area
5 Pa = Force/ 9×10^-4
Force = 45×10^-4
Area of base = 0.03m×0.03m
= 0.0009 m^2
So, we can write as 9×10^-4
Pressure = Force /Area
5 Pa = Force/ 9×10^-4
Force = 45×10^-4
chiragmalik7890:
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