Question

The pressure exerted by water (densityp = 1000 kg/m?) on the bottom surface (2m
4m) of tank having dimensions 2m x 4m x 2m is (g = 9.8m/s2)
(A) 2.96 x 105 Pa
(B) 1.9 x 104 Pa
(C) 1.80 x 104 Pa
(D) 1.96 x 104 Pa​

Answer 1

Answer:

Pressure exerted by fluid= density (rho)×acceleration due to gravity (g)× height of container(h)

so, data given, vol=(2×4)×2m³

and, area= (2×4)m²

so height(h)= 2m [Just divide, volume/area= height]

density(rho)= 1000kg/m³

acceleration due to gravity (g)= 9.8m/s²

so pressure= (rho)×(g)×(h)

= 1000×9.8×2 Pa

= 19.6×10³ Pa

=1.96×10⁴ Pa

rho is a symbol used to denote density in this question [ρ]= rho