Question

The pressure exerted on a surface of area 0.5 m² due to an object placed on it is 6 x 10³ Pa. Calculate the force acting on the surface​

Answer 1

Answer:

To Find :

The Thrust Acting on the Surface .

Given :

Area of Contact = 0.5 m²

Pressure Exerted = 6 × 10³ Pa.

We Know :

Where,

P = Pressure Exerted

F = Force Acting on the surface

A = Area of Contact

Solution :

By putting the given values in the Formula , we get :

Given :

Area = 0.5 cm^{2}

Pressure = 6 × 10³ Pa

Let the Force Acting on the Surface be F N.

Hence the Force Acting on the Surface is 3 × 10³ N.

Analysis :

The Pressure is Directly Proportional to the Force applied .i.e More the Force applied , more will be the Pressure Exerted.

The pressure is Inversely proportional to the area of contact i.e More is the Area lesser is the Pressure Exerted or vice-versa.

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Answer 2

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The froce acting on the surface is 3 × 10³

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Explaination :-

➮ Given :-

• Area = 0.5 m²
• Pressure Exerted = 6 × 10³ Pa

➮ To find :-

the force acting on the surface

➮ Calculation :-

we know,

$\longrightarrow \: { \bf pressure = \frac{froce}{area}}$

by Substitute all the given value in the formula

$\longrightarrow \sf 6 \times {10}^{3} = \frac{force}{0.5 }$

$\longrightarrow \sf froce = 6 \times {10}^{3} \times 0.5$

$\longrightarrow \boxed { \bf froce = 3 \times {10}^{3} N}$

Hence, the froce acting on the surface is 3×10³N