Physics, asked by Mdahad24, 9 months ago

the pressure exerted on a table when a cube of side 10cm and mass 5kg is kept on it will be a) 49kpa b)4.9kpa c) 490kpa d) 0.49kpa​

Answers

Answered by ferozemulani
7

Explanation:

weight of cube = 5*9.8 = 49 N

area of base of a cube = 0.1^2

= 0.01 m^2

pressure = weight/area = 49/0.01

= 4.9 *10^3 = 4.9 kPa

option b is correct

Answered by donp
5

Answer:

.49kpa

Explanation:

Pressure =force /area

Here

  • Force. =mg

Where m=5kg..

  • Force =5*9.8=49
  • Sideof the cube= 10cm =.1m
  • Base area of cube = 0.01m^2

Pressure =49/0.01=490pa=. 49kpa

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