the pressure exerted on a table when a cube of side 10cm and mass 5kg is kept on it will be a) 49kpa b)4.9kpa c) 490kpa d) 0.49kpa
Answers
Answered by
7
Explanation:
weight of cube = 5*9.8 = 49 N
area of base of a cube = 0.1^2
= 0.01 m^2
pressure = weight/area = 49/0.01
= 4.9 *10^3 = 4.9 kPa
option b is correct
Answered by
5
Answer:
.49kpa
Explanation:
Pressure =force /area
Here
- Force. =mg
Where m=5kg..
- Force =5*9.8=49
- Sideof the cube= 10cm =.1m
- Base area of cube = 0.01m^2
Pressure =49/0.01=490pa=. 49kpa
Similar questions