The pressure in each of the four tyre of a car is 1.5*10^4 kgf/m^2 while each tyre has area of contact 25*10^-4 m^2 find the wait of the car.
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Given, pressure, P=2.0×10
5
;
area of tyre, A=0.024m
2
;
weight of automobile, W=?
Since, automobile is supported by four tyres, load or force (F) on each tyre is one fourth of the weight of the automobile, i.e., F = W/4
Pressure, P=
A
F
or P=
A
(W/4)
=
4A
W
W=4AP=4×0.024×2×10
5
=1.92×10
4
N.
Hence, the weight of the automobile is =1.92×10
4
.
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