The pressure inside a soap bubble of radius 1 cm balance 2cm in a column of oil of specific gravity 0.80. calculate surface tension of soap solution?
Answers
Answered by
4
pressure at the depth of 2 mm in oil
= 0.8 * 1000 kg/m² * 9.81 m/sec² * 0.002 m
= 15.696 N/m²
P = P2 - P1
= excess pressure of a soap bubble = pressure inside - pressure outside
= 4 S / R , where S = surface tension and R = radius of the bubble.
S = P * R / 4 = 15.696 * 0.01 m / 4 = 0.03924 N/m
if there is some different answer, perhaps the given values of radii are not correct..
= 0.8 * 1000 kg/m² * 9.81 m/sec² * 0.002 m
= 15.696 N/m²
P = P2 - P1
= excess pressure of a soap bubble = pressure inside - pressure outside
= 4 S / R , where S = surface tension and R = radius of the bubble.
S = P * R / 4 = 15.696 * 0.01 m / 4 = 0.03924 N/m
if there is some different answer, perhaps the given values of radii are not correct..
Similar questions