Question

The pressure inside a tyre is 4 times that of atmosphere. If the tyre bursts suddenly at temperature 300 K, what will be the new temperature?(a) $300(4)^{\frac{7}{2}}$(b) $300(4)^{\frac{2}{7}}$(c) $300(2)^{\frac{7}{2}}$(d) $300(4)^{\frac{-2}{7}}$

Answer 1

Hey

The pressure inside a tyre is 4 times that of atmosphere. If the tyre bursts suddenly at temperature 300 K, what will be the new temperature?(a) $300(4)^{\frac{7}{2}}$(b) $300(4)^{\frac{2}{7}}$(c) $300(2)^{\frac{7}{2}}$(d) $300(4)^{\frac{-2}{7}}$

D correct

Answer 2

The pressure inside a tyre is 4 times that of atmosphere. If the tyre bursts suddenly at temperature 300 K, what will be the new temperature?(a) $300(4)^{\frac{7}{2}}$(b) $300(4)^{\frac{2}{7}}$(c) $300(2)^{\frac{7}{2}}$(d) $300(4)^{\frac{-2}{7}}$