Question

The pressure of 20L of a gas kept at 300k if found to be 2 atoms. If the pressur is increased to 3 atom at the same temperature. What will be the new volume
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Answer 1

Answer:

According to Boylers law , P

V

=a constant

Therefore, P

1

V

1

=P

2

V

2

Here, P

1

=2atmV

1

=20LP

2

=3atmV

2

=?

∴2×20=3×V

2

Thus, V

2

=

3

2×20

=13.3L