Question

The pressure of a 1.4 mixture of dihydrogen and dioxygen enclosed in a
vessel is one atmosphere. What would be the partial pressure of dioxygen?
) 0.8x105 atm 2) 0.008 N m-2
3) 8x104 N m-2
4) 0.25 atm
How do I solve this

Answer 1

Answer:

first order reaction is carried out with an initial concentration of 10 ML–1 and 80% of the reactant changes into the product. Now if the same reaction is carried out with an initial concentration of 5 ML–1, the percentage of reactant changing to the product i

For the 10ML-1 concentration,

k = ln(10/2)/t.....(1)

and

for 5ML-1

k = ln(5/x)/t..............(2)

From both the eqns. we get,

5 = 5/x

x = 1

that means % that gets converted to product,

4*100/5 => 80%

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