Question

the pressure of a fixed mass of air is 1.01×10^5 Pa . It is compressed slowly keeping its temperature constant . Then what is the bulk modulus of air is

Answer 1

Explanation:

P=1.01×10

5

Pa

Temperature is constant ⇒ isothermal process

⇒

⇒

B

PV= constant

P(ΔV)+(ΔP)(V)=0

V

ΔV

=−

P

ΔP

⟶(1)

=

ΔV/V

−ΔP

⟶ (2)

⇒B=P⟶ using (1)

⇒B=1.01×10

5

Pa