Question

The pressure of a gas=1.5 is suddenly raised to 8 times.calculate how many times the volume of gas will become.

Answer 1

Answer:

The volume will become 0.04166 time of previous volume

Explanation:

We have given pressure $P_1=1.5$

Let the volume of the gas is $V_1$

Now pressure is increases to 8 times

So $P_2=8\times 1.5=12$

From the ideal gas equation we know that $P_1V_1=P_2V_2$

$1.5\times V_1=12\times V_2$

$V_2=0.04166V_1$

So the volume will become 0.04166 time of previous volume