Question

The pressure of a gas contained in a cylinder with a movable piston is 300 Pa. The area of the
piston is 0.5 m2. The force that is exerted on the piston is (75 x Y) N. What is the value of y?​

Answer 1

Answer:

• The value of Y = 2.

Explanation:

Given:-

• Pressure of gas ,P = 300Pa
• Area of Piston ,A = 0.5m²

To Find:-

• Force exerted on the Piston ,F

Solution:-

According to the Question

It is given that pressure of a gas contained in a cylinder with a movable piston is 300 Pa. The area of the piston is 0.5 m².

We have to calculate the the force exerted on the Piston .

As we know the relationship between Force , Area & Pressure.

• P = F/A

Where,

• P denote Pressure
• F denote Force
• A denote area

Putting the value we get

→ 300 = F/0.5

→ F = 300×0.5

→ F = 150 N

Since, the force is 150 newton.

as

→ 75 × Y = 150

→ Y = 150/75

→ Y = 2

• So the value of y = 2

Answer 2

Answer:-

• Pressure=300Pa
• Area=0.5m^2
• Force=(75×Y)N

We have to find y.

$\boxed{\sf Pressure=\dfrac{Force}{Area}}$

$\\ \sf \longmapsto Force=Pressure\times Area$

$\\ \sf \longmapsto 75\times Y=300\times 0.5$

$\\ \sf \longmapsto 75Y=150$

$\\ \sf \longmapsto Y=\dfrac{150}{75}$

$\\ \sf \longmapsto Y=2$

Hence value of Y is 2.