the pressure of a liquid at a given surface is 40000 pa . find the depth of the liquid
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Answer:
Pressure of water on the ground floor =P
1
=40000Pa
Pressure of water on the first floor =P
2
=10000Pa
Density, ρ=1000kg/m
3
We know that, P
1
−P
2
=ρgh
⇒40000−10000=1000×10×h
∴h=3m
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