Question

The pressure of a substance is 1105mmHg at triple point of the substance. What is the temperature of the substance if the pressure is 1750mmHg?

Answer 1

Answer:

triple point of water is 273.16 K

according to gay lussac law

when volume is constant then pressure is directly proportional to temprature

so,(P1/T1)=(P2/T2)

so,T2=(P2×T1)/P1

so,T2=(1750×273.16)/1105

so,T2=432.60 K

so your answer is 432.60 K

thanks