Physics, asked by harishmajb, 3 months ago

the pressure of air inside a soap bubble is 1mm of mercury greater than the atmospheric press
ure.what is the diameter of the bubble surface tension=0.043N/m​

Answers

Answered by nancy359
0

ANSWER:-

1 cm

Explanation:

Given:-

A soap bubble, having radius of 1 mm, is blown from a detergent solution having a surface tension of 2.5 × 10–2 N/m. The pressure inside the bubble equals at a point Z0 below the free surface of water in a container. Taking g = 10 m/s2, density of water = 103 kg/m3, the value of Z0 is

We know that Guage pressure = ρgZo and excess pressure = 4 T /R

k + 4 T/R = k + ρ g Zo

4 T / R = ρ g Zo

Zo = 4 T / R ρ g

Zo = 4 x 2.5 x 10^-2 / 10^-3 x 1000 x 10

Zo = 10^-2

Zo = 1 cm

Answered by devapriyasy
0

Answer:

Excess pressure inside a bubble,p=4S/R

R=4S/P

= 4×.043/(1×10^-3)×13600×9.8

=1.29×10^-2m

Diameter of the bubble=2.58×10^-2m

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