The pressure of sodium vapour in a 1l container is 10 torr at 1000°c
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Answered by
14
n = PV/RT = (1/760) 1 / (0.082057 x 1273.15)
n = 8.82x10^-5 mole
atoms = 8.82x10^-5 x 6.022x10^23 = 5.31 x 10^19 atoms of Na
Answered by
11
Answer:7.6×10^19
Explanation:PV=nRT,equation of state.
n=PV/RT
=1×10/760×0.0821×1273
=1.26×10^-4
Number of Na atoms=1.26×10^-4×6.02×10^23
=7.6×10^19
hope it helps...
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