Question

the pressure of the atmosphere is 2×10^-6 mm about 100 miles above from the earth and temperature is -180°c .How many moles are there in 1ml gas at this attitude ?

Answer 1

$according \: to \: question \: \\ \\ p = \frac{2 \times \: 10 { - }^{6} }{760} atm \\ \\ v = 1ml = \frac{1}{1000 \: litre} \\ \\ pv \: = \: nRt \\ \\ \frac{2 \times {10 }^{ - 2} }{6} 4 \times {10}^{ - 3} \\ \\ = n \times 0.0821 \times 93 \\ \\ n = 3.45 \times {10}^{ - 13}$

be create a brainly.

regards: rishi arya

Answer 2

Explanation:

Given

P=2×10−6760P=2×10−6760atm

T = -180 + 273 = 93K

V = 1 mL = 1100011000litre

PV=nRT

2×10−6760×10−3=n×0.0821×932×10−6760×10−3=n×0.0821×93

n=3.45×10−13molen=3.45×10−13mole

Hence answer is (B)