Question

The pressure of water on the ground floor is 40,000 Pa and on the first floor is 10,000 Pa. Find the height of the first floor.
(Take: density of water = 1000kg / m^3 and g = 10 m/s^2)

The answer involves substracting 40,000 and 10,000 can anyone tell me why is that done?

Please help, I will mark you brainiest.

Answer 1

Check this attachment :-)

Answer 2

Explanation:

ΔP = p0 - p1 = ρ×g×Δh

where Δh is height of first floor from ground. p0 and p1 are water pressure at ground and first floor respectively

40000-10000 = 30000 = 1000×9.8×Δh