Question

The pressure of water on the
ground floor os 50000 Pa and
at the first floor is 20000
Pa Find the height of the
first floor. Take density of
water 10(3) kg/m3 and g.=10m/s2​

Answer 1

Given:

Pressure on ground floor $P_{1} = 50000$ Pa

Pressure on first floor $P_{2} = 20000$ Pa

Density of water $\rho = 10^{3} \frac{Kg}{m^{2} }$

Gravitational constant $g = 10 \frac{m}{s^{2} }$

To Find:

Height of the first floor,

From the formula of pressure difference,

  $P_{1} -P_{2} = \rho g h$

For finding height,

  $50000-20000 = 1000 \times 9.8 \times h$

  $h = 3.061$ m

Therefore, the height of the first floor is 3.061 m