The pressure on one mole of gas at S.T.P. is doubled and temperature is raised to 546 kelvin . What is the final volume of the gas ( one mole of a gas occupies a volume of 22.4 liters at S.T.P.)
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if p1 =x then p2=2x
v1=22.4 v2=?
T1= 298K (std temp)
T2=546K
(p1×v1)/T1 =(p2×v2)/T2
therefore v2= (546×22.4)÷(2×298)
= 20.52L
v1=22.4 v2=?
T1= 298K (std temp)
T2=546K
(p1×v1)/T1 =(p2×v2)/T2
therefore v2= (546×22.4)÷(2×298)
= 20.52L
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