Question

The pressure on the legs of a table is 10 N cm. Given that the table has four legs and
the contact surface of each leg on the floor is 25 cm². Calculate the weight of the
table. (Take g = 10 N kg")

Answer 1

Answer:

Given :  a boy standing on both feet   weight of the boy is 40kg.

area of contact of each shoe is 6 cm by 25 cm  

1kg wt =10 N

To Find : pressure exerted on the floor by   boy

Solution :

1kg wt =10 N

=>  40kg.wt =40 * 10  = 400 N

area of contact of each shoe  = 6cm x 25 cm

= (6/100)  m x (25/100)   m

= 15/1000  m²

There are two shoes so total area

= 2 *  15/1000  m²

= 30 /1000  m²

= 3/100 m²

Pressure = Force / Area

=> Pressure  = 400 / ( 3/100)

=> Pressure  = 40000 /3  N/m² or Pa

=>  Pressure  =  40/3   kN/m² or kPa

=>  Pressure  =  13.33 kN/m² or kPa

pressure exerted on the floor by boy =  13.33 kN/m² or kPa

Explanation:

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Answer 2

The diameter of the circular track is given as 200 m. That is, 2r=200 m.
From this radius is calculated as Radius, r = 100 m.
In 40 sec the athlete complete one round. So, in 2 mins and 20 secs, that is, 140 sec the athlete will complete = 140 / 40 = 3.5 (three and a half) rounds.
One round is considered as the circumference of the circular track.
The distance covered in 140 sec = 2πr×3.5=2×3.14×100×3.5=2200 m.
For each complete round the displacement is zero. Therefore for 3 complete rounds, the displacement will be zero.
At the end of his motion, the athlete will be in the diametrically opposite position. That is, displacement = diameter = 200 m.
Hence, the distance covered is 2200 m and the displacement is 200 m.