Question

The pressure on the tyres of a sedan car is P. The
contact surface of each tyre with the floor is A. Find
the new contact surface of each tyre when air is
released from the tyre and the pressure of the car is
reduced to 0.75 P.​

Answer 1

Answer:

a2=1.33a1

Explanation:

force = pressure×area=p×4a ( since there are four tyres)=4pa........(1)

now force =pressure×area

=0.75p×4a2..........(2)

equating (1) and (2) we get

4pa1=0.75p×4a2

a2=a1/0.75

a2=1.33a1

Answer 2

$A=\frac{F}{0.75P}$ area becomes four-third of the initial area.

Explanation:

The downforce on the car remains constant due to unchanged mass of the car, so:

$F=P.A$

$F=0.75P\times A$

$A=\frac{F}{0.75P}$

In this case the area of contact between the tyres and the ground increases.

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TOPIC: camber

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