Question

The pressure, P volume V and temperature T of a
gas are related as PV = nRT. If the temperature
increases by 2 K at constant volume due to an
increase in pressure of 3%, the initial temperature
of the gas is​

Answer 1

The given relation is P=

V

αT−βT

2

⟹ V=

P

αT−βT

2

Differentiating we get, dV=

P

α−2βT

dT ............(1)

Work done by the gas W=∫PdV

∴ W=∫

T

1

T

2

(α−2βT)dT

⟹ W=αT

∣

∣

∣

∣

∣

T

1

T

2

−2β×

2

T

2

∣

∣

∣

∣

∣

T

1

T

2

=α(T

2

−T

1

)−β(T

2

2

−T

1

2

Answer 2

Answer:

200/3K

Explanation:

This is the correct answer.