The price for one ticket of cinema is rs. (x2 – 3x + 9). How many tickets are
purchased in rs. (x4 + 9x2 + 81)?
Answers
Answered by
24
Given:
The price of one cinema ticket = (x²-3x+9) Rs.
To find:
We have to find the number of tickets that can be purchased in Rs.(x⁴+9x²+81)
Solution:
Let us assume that 'a' no.of tickets can be purchased in Rs.(x⁴+9x²+81)
Now, 1 ticket costs - x²-3x+9
'a' tickets costs - x⁴+9x²+81
Applying cross multiplication, we write
a( x²-3x+9) = x⁴+9x²+81
a = ( x⁴+9x²+81) / ( x²-3x+9)
a = x²+3x+9 [Refer to figure 1 attched below,division of
polynomials is described in detail]
∴x²+3x+9 tickets can be purchased in Rs.(x⁴+9x²+81)
Attachments:
Answered by
2
Answer:
the is ans you can rite tu his answer
Attachments:
Similar questions