Question

The Price of 2 hockey balls and 5 squash balls is Rs. 75 whereas 3 hockey balls and 2
squash balls cost Rs 85. Find the price of each. Solve by using elimination method

Answer 1

$\huge\boxed{\fcolorbox{blue}{orange}{HELLO\:MATE}}$

Let the price if each hockey ball be x and that of each squash ball be y.

GIVEN

→ The cost of 2 hockey balls and 5 squash balls is Rs75.

I. e. $\large{\red{ 2x + 5 y = Rs75}}$

→The cost of 3 hockey balls and 2 squash balls is Rs85.

I. e. $\large{\red{ 3x + 2y = Rs85}}$

TO FIND:

The price of each hockey and squash ball that is x and y respectively.

SOLUTION:

IN First case:

$2x + 5y = Rs 75$

On multiplying both sides by 3 , we have;

=>$3(2x + 5y ) = Rs75×3$

=>$6x + 15y =Rs 225$ .......... (1)

In second case:

$3x + 2y = Rs85$

On multiplying both sides by 2 , we have;

$2(3x+2y) =Rs 85×2$

=>$6x +4y = Rs170$ ......... (2)

$\large\red{\boxed{ equation(1) -equation (2) }}$

=>$6x + 15y =Rs 225$

- $-6x ±4y = ±Rs170$

__________________________

=>$11y = Rs 55$

=>$y =\dfrac{Rs55}{11}$

=>$y = Rs 5$

Therefore cost of the squash ball is y =Rs5

Now, from equation 2.

=>$6x +4y = Rs170$

=>$6x +4×5=Rs170.$

=>$6x + 20 =Rs 170$

=>$6x =Rs(170-20)$

=>$x =\dfrac{Rs150}{6}$

=>$x = Rs25$

Therefore cost of hockey ball is Rs25.

$\huge\purple{\boxed{Hockey \:ball=Rs25}}$

$\huge\green{\boxed{Squash \:ball=Rs5}}$