Question

The price of 2 packets of chocolates and 3 packets of wafers is 7 5400. If a packet of chocolate costs 700 more than a packet of wafers, find the price of each.​

Answer 1

let price of chocolates and wafer are x and y

so... a/q,x-y=700 2x-2y=1400

and 2x

Answer 2

$\bold{\large{\red{\tt{ANSWER}}}}$

Let the cost of a packet of chocolates be Rs. x and the cost of a packet of wafers be Rs. y.

This implies,

$2(x) + 3(y) = 5400 - - > 1$

A packet of chocolates costs Rs. 700 more than a packet of wafers.

Therefore,

$x = 700 + y$

$Substituting \: x = 700 + y \: in \: equation \: 1$

$- > 2(700 + y) + 3 \times y = 5400$

$- > 1400 + 2y + 3y = 5400$

$- > 5y = 5400 - 1400$

$- > 5y = 4000$

$- > y = \frac{4000}{5}$

$- > y = 800$

Now ,

$x = 700 + y$

$- > x = 700 + 800$

$- > x = 1500$

Therefore, the price of a packet of chocolates is Rs. 1500 and the price of a packet of wafers is Rs. 800

I hope it helps u dear friend ^_^♡♡