Question

The price of 2 tables and 3 chairs is rs 340 but a table cost rs20 more than a chair find the price of each

Answer 1

let price of chair be x
and table be x+20
then,
$2(x + 20) + 3x = 340 \\ 2x + 40 + 3x = 340 \\ 5x = 340 - 40 \\ x = \frac{300}{5 } = 60$
so price of one table=
$x + 20 = 60 + 20 = 80$
price of one chair=60

Answer 2

LET TAKE THAT PRICE OF
CHAIRS AS X
THEN TABLE PRICE X+20

THREE CHAIRS PRICE 3X
TWO TABLES PRICE 2(X+20)

3X+2X(X+20) = 340
3X + 2X + 40 = 340
5X +40 = 340
5X = 340-40
5X = 300
X = 300/5
X = 60

SO VALUE OF
CHAIR = X = ₹ 60
TABLE = X+20 = 60+20 = ₹80