Question

The price of 3 bedcovers and 5 table covers is 2600. A bedcover
the cost 80 more than a table cover. Find the cost of each
​

Answer 1

Answer:

Let the cost of a table be Rs.x and that of a chair be Rs.y.Then

2x+3y=2000 ........(1)

3x+2y=2500 ........(2)

Multiplying equation (1) by 3 and (2) by 1, we get

6x+9y=6000 .........(3)

6x+4y=5000 .........(4)

Subtracting (4) from (3) we get

6x+4y−6x−9y=5000−6000

⇒−5y=−1000

⇒y=

−5

−1000

=200

∴y=200

Put y=200 in (3) we get

2x+3×200=2000

⇒2x=2000−600=1400

⇒x=

2

1400

=700

So,Cost of a table=Rs.700 and cost of a chair =Rs.200

Hence cost of 1 table and 5 chairs=1×700+5×200=700+1000=Rs.1700